5th no
A wedge of height 'h'is released from rest with a light particles P placed on it as shown.the wedge slides down an incline which makes an angle  θ  with horizontal.All the surface are smooth ,P will reach the surface of the surface of the incline in time. ( a ) 2 h g sin 2 θ             ( b ) 2 h g sin θ cos θ           ( c ) 2 h g tan θ           ( d ) 2 h g cos 2 θ

I think the answer is A) root 2h/g sin2theta If its correct letme know HOPE IT HELPS)
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But Give me solving method
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can u just tell if the answer is correct or not only then I can give u solving method
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Yes Answer Is Correct
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Wedge slides with acceleration gsinθ. Pseudo acceleration of particle is upward. Acceleration of P along horizontal is gsinθcosθ. ==> hcotθ=1/2*a*t²...
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