6 The resultant amplitude due to super position of two SHM is X1=10sin(wt+300)cm X2= -10cos(wt-600)cm - Physics - System Of Particles And Rotational Motion

Question

6 The resultant amplitude due to super position of two SHM is
X1=10sin(wt+300)cm X2= -10cos(wt-600)cm

Akansha Tyagi · Accepted Answer

X=X1+X2=10sin(ωt+30)-10cos(ωt-60)X=10sin(ωt-30)-10cos(ωt-60+90)X=10sin(ωt-30)+10sin(ωt+30)   =10[2sinωtcos30]X=103

6.The resultant amplitude due to super position of two SHM is X1=10sin(wt+300)cm X2= -10cos(wt-600)cm.