6)What is the smallest natural number k, for which the polynomial 2x ^2 + kx + 6 can be written as a product of two first degree polynomials. Write down the polynomial using k and express it as the product of two first degree polynomials

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D>0 i.e. b^2-4ac>0 we get k^2>= 48(k square greater than or equal to 48) hence minimum natural no. Which satisfies it is 7 hence k=7 now the polynomial would look like 2x^2+7x+6 which can be written as 2x^2+4x+3x+6 i.e. 2x(x+2)+3(x+2) i.e. (2x+3)(x+2). Also tell me from where have you taken this question
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