60g of ice at 0 C is added to 20g of water at 40 The final temperature attained - Science - Friction

Question

60g of ice at 0°C is added to 20g of water at 40° The
final temperature attained by the mixture is (given
latent heat of melting of ice = 80 cal/g and specific heat of
water is 1 cal/g/°C)
(a) 0°C (b) 20°C (c) 10°C (d) 5°C
Please Explain?

Jyoti Pant · Accepted Answer

Please refer to the following link:

https://www meritnation
com/ask-answer/question/50g-of-ice-at-0-degree-c-is-mixed-with-50g-water-at-2o-degre/physics/2777161

60g of ice at 0°C is added to 20g of water at 40°. The final temperature attained by the mixture is (given latent heat of melting of ice = 80 cal/g and specific heat of water is 1 cal/g/°C) (a) 0°C (b) 20°C (c) 10°C (d) 5°C Please Explain?

60g of ice at 0°C is added to 20g of water at 40°. The final temperature attained by the mixture is (given

latent heat of melting of ice = 80 cal/g and specific heat of water is 1 cal/g/°C)

(a) 0°C (b) 20°C (c) 10°C (d) 5°C

Please Explain?