61. The percentage error in measurement of a physical quantity m, given by m = pi tan theta, is minimum when
i) theta = 45o

ii) theta = 90o
iii) theta = 60o
iv) theta = 30o

Dear Student,
m=πtanθby differentiating both sides,we getdm=πSec2θdividing both sides with m,we getdmm=πSec2θπtanθ=2Sin2θif percentage error is minimum,then Sin2θ is maximum,soθ=45°option(i) is correct.
Hope this information will clear your doubts about topic.

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