7) Find the equation of tangent to the curve y=x4-6x3+13x2-10x+5 at point x=1, y=0 8) Find the equation of - Maths - Application of Derivatives

Question

7) Find the equation of tangent to the curve y = x 4 - 6 x 3 + 13 x
2 - 10 x + 5   a t   p o i n t   x = 1 ,   y =
0
8) Find the equation of tangent to the curve 4 x 2 + 9 y 2 = 36
  a t   t h e   p o i n t   (   3  
cos   θ ,   2   sin   θ )

Amit Shukla · Accepted Answer

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Q 8 
https://www meritnation
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7) Find the equation of tangent to the curve y = x 4 - 6 x 3 + 13 x 2 - 10 x + 5 a t p o i n t x = 1 , y = 0 . 8) Find the equation of tangent to the curve 4 x 2 + 9 y 2 = 36 a t t h e p o i n t ( 3 cos θ , 2 sin θ ) .

7) Find the equation of tangent to the curve $y = x^{4} - 6 x^{3} + 13 x^{2} - 10 x + 5 a t p o i n t x = 1, y = 0 .$
8) Find the equation of tangent to the curve $4 x^{2} + 9 y^{2} = 36 a t t h e p o i n t (3 \cos θ, 2 \sin θ) .$