7) What is the effective area of charcoal occupied per ammonia molecule.
$(A) \frac{1}{2} \sqrt{3} \times 10^{- 20} m^{2} (B) 4 \sqrt{3} \times 10^{- 20} m^{2} (C) 2 \sqrt{3} \times 10^{- 20} m^{2} (D) 8 \sqrt{3} \times 10^{- 20} m^{2}$

Question

7) What is the effective area of charcoal occupied per ammonia
molecule
( A ) 1 2 3 × 10 - 20   m 2 ( B )   4 3 × 10
- 20   m 2 ( C )   2 3 × 10 - 20   m 2 ( D )
  8 3 × 10 - 20   m 2

Vartika Jain · Accepted Answer

Dear Student,

Surafce are of 1 g of activated charcoal =103 m2Therefore, surafce area of 103 g of activated charcoal = 103×103=1043Now, NA= 6
022×1023Moles of NH3=  5M×0
1 L= 0
5 molHence, effective area = 0
5×104×36×1023=83×10-20 m2

7) What is the effective area of charcoal occupied per ammonia molecule. ( A ) 1 2 3 × 10 - 20 m 2 ( B ) 4 3 × 10 - 20 m 2 ( C ) 2 3 × 10 - 20 m 2 ( D ) 8 3 × 10 - 20 m 2

7) What is the effective area of charcoal occupied per ammonia molecule.
$(A) \frac{1}{2} \sqrt{3} \times 10^{- 20} m^{2} (B) 4 \sqrt{3} \times 10^{- 20} m^{2} (C) 2 \sqrt{3} \times 10^{- 20} m^{2} (D) 8 \sqrt{3} \times 10^{- 20} m^{2}$