71) If α is a repeated root of a x 2 + b x + c = 0   t h e n   l i m x α   sin   ( a x 2 + b x + c ) ( x - α ) 2   i s

(1) 0
(2) a
(3) b
(4) c

Dear Student,
Please find below the solution to the asked query:

The general formula is limxa sinfxfx=1 where limxa fx=0L=limxα sinax2+bx+cx-α2As α is repeated root of ax2+bx+c, henceax2+bx+c=ax-α2HenceL=limxα sinax-α2x-α2=alimxα sinax-α2ax-α2 Here fx=ax-α2=a×1=a Answer

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  • 1
ax^2+bx+c=a(x-alpha)^2

so answer will be a
  • 0
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