8 charged water droplets each with radius 1 mm n charge 10 RAISE TO POWER MINUS 10 collapse to form a single drop. cal. The electric field of bigger drop. ? explain with ans Share with your friends Share 1 Vikas answered this Answerthe electric feild of drop of radius r carrying a charge q is E=14πεqr2charge on 8 drops Q=8q radius of the big drop =813×r=2rtherefore the electri felid E due to big drop is E = 14πε8q(2r)2=14πε2qr2where r= 1×10-3 m and q = 10-10 coloumbE= 9×1092×10-1010-6=18×105 -1 View Full Answer Simran answered this pls explain this question? -1