8 charged water droplets each with radius 1 mm n charge 10 RAISE TO POWER MINUS 10 collapse to form a single drop. cal. The electric field of bigger drop. ? explain with ans

Answerthe electric feild of drop of radius r carrying a charge q is E=14πεqr2charge on 8 drops Q=8q radius of the big drop =813×r=2rtherefore the electri felid E due to big drop is E = 14πε8q(2r)2=14πε2qr2where  r= 1×10-3 m   and  q = 10-10 coloumbE= 9×1092×10-1010-6=18×105 

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pls explain this question?
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