8:- For what value of n , are the nth terms of two APs: 60,62,64... and -10,-3,4,11....equal ?

First  ap is 60,62,64...

Second Ap is -10,-3,4,11...

       lets equate both term ap's nth term.
an= a+(n-1)d = an = a+(n-1)d
an= 60+(n-1)2 = an = -10+(n-1)7
an= 60+2n-2 = an = -10+7n-7
an= 60+2n-2+10-7n+7=0
an=60+10+7-2+2n-7n=0
an=75-5n=0
an=75=5n
an=15 answer