8) In how many ways can 5 members forming a committee out of 10, so that (i) two particular members must be included (ii) two particular members must not be included

Question

8) In how many ways can 5 members forming a committee out of 10, so
that (i) two particular members must be included (ii) two
particular members must not be included

Rishabh Mittal · Accepted Answer

Total number of members=101 When two particular members are included , then we have to select 3 members out of 8
Number of ways=c38=8!5! 3!=8×7×6×5!5!×3×2 =56 ways
2 When two particular members are not included , then we have to select 5 members out of 8
Number of ways=c58=8!5! 3!=8×7×6×5!5!×3×2 =56 ways