# 8 q pllll

The computation are expressed below,

$2N{H}_{3}+C{O}_{2}\to N{H}_{2}-CO-N{H}_{2}+H2O\phantom{\rule{0ex}{0ex}}molesofurea=\frac{999.6\times {10}^{3}}{60}=16.66\times {10}^{3}\phantom{\rule{0ex}{0ex}}{C}_{n}{H}_{2n+2}+{O}_{2}\to nC{O}_{2}+{H}_{2}O\phantom{\rule{0ex}{0ex}}\frac{16.66\times {10}^{3}}{n}\times [12n+(2n+2\left)\right]=236\times {10}^{3}\phantom{\rule{0ex}{0ex}}n\cong 12\phantom{\rule{0ex}{0ex}}Hencethemolecularformulaofhydrocarbonis,\phantom{\rule{0ex}{0ex}}{C}_{12}{H}_{26}$

Regards.

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