8sin theta = 2 - cos theta find sin theta Share with your friends Share 0 Ishwarmani answered this Dear Student, Please find below the solution to the asked query: We have,8sinθ=2-cosθSquaring both sides, we get64sin2θ=4+cos2θ-4cosθ⇒641-cos2θ=4+cos2θ-4cosθ⇒64-64cos2θ=4+cos2θ-4cosθ⇒65cos2θ-4cosθ-60=0Now, cosθ=--4±-42-4×65×-602×65=4±16+15600130=4±415616130=4±1661130=2±86165If cosθ=2+86165,thensin2θ=1-2+861652=4225-4+3904+32614225=4225-3908-32614225=317-32614225=256+61-32614225=16-6124225⇒sinθ=16-6124225⇒sinθ=16-6165If cosθ=2-86165,thensin2θ=1-2-861652=4225-4+3904-32614225=4225-3908+32614225=317+32614225=256+61+32614225=16+6124225⇒sinθ=16+6124225⇒sinθ=16+6165 Regards 0 View Full Answer
