900 ml of pure & dry O2 is subjected to O2 seilent electric discharge, so that after a time 10 min. volume of ozonized oxygen is found to be 870 ml. Now, average rate of reaction in this interval is (in ml/min)
(1) 3                       (2) 9                    (3) 90                   (4) 60

Dear student, 
Rate of reaction = change in volume of O2 / change in time
                            = 870-900 / 10
                             = -30 / 10
                             = -3  ml min-1
It is negative because volume is decreasing with time.
So the answer is ( 1 ) i.e 3 when only magnitude is considered

Regards

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