94. A solution is a mixture of 0.06 M KCI and 0.06 M KI. AgNO3 solution is being added drop by drop till AgCl starts precipitating (Ksp AgCl = l × 10 - 10 and Ksp Agl = 4 × 10 - 16 ). The concentration of Iodideion at this stage will be nearly equal to • (1) 4.0 x 10-5 M (2) 2.4 x 10-7 M (3) 2.0 x 10-8 M (4) 4 x 10-8 M Share with your friends Share 25 Vartika Jain answered this Dear Student, Ksp(AgCl) = [Ag+][Cl-]KCl is a strong electrolyte, so [KCl]=[Cl-]=0.06 MSo, concentration of Ag+ when AgCl starts precipitating is[Ag+] =Ksp(AgCl)[Cl-] =1×10-100.06Now, Ksp(AgI) = [Ag+][I-]So, [I-]=Ksp(AgI) [Ag+] =4×10-16×0.0610-10 =0.24×10-6 =2.4×10-7Hence, correct answer is (2) 41 View Full Answer