94.  A solution is a mixture of 0.06 M KCI and 0.06 M KI. AgNO3  solution is being added drop by drop till AgCl starts precipitating (Ksp  AgCl = l × 10 - 10 and Ksp  Agl = 4 × 10 - 16 ). The concentration of Iodideion at this stage will be nearly equal to •
(1) 4.0 x 10-5 M
(2) 2.4 x 10-7 M
(3) 2.0 x 10-8 M
(4) 4 x 10-8 M
 

Dear Student,

Ksp(AgCl) = [Ag+][Cl-]KCl is a strong electrolyte, so [KCl]=[Cl-]=0.06 MSo, concentration of Ag+ when AgCl starts precipitating is[Ag+] =Ksp(AgCl)[Cl-]           =1×10-100.06Now, Ksp(AgI)= [Ag+][I-]So, [I-]=Ksp(AgI) [Ag+]             =4×10-16×0.0610-10             =0.24×10-6             =2.4×10-7Hence, correct answer is (2) 

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