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Dear Student,

Please find below the solution to the asked query:

We know in magic square sum of each row, column, and diagonal is one constant number .

Here , Sum of 4th row  =  12 + 7 + 11 + 0 =  30 , So

Sum of 1st column =  a + 2 + 1 + 12 = a + 15 , Then

a + 15 =  30 ,  (  As we know sum of each row, column, and diagonal is = 30 )

a = 15

And Sum of 1st row  =  a + 4 + 8 + b =  a + b + 12 , So

a + b + 12 =  30 , Substitute value of ' a ' and get

15 + b + 12 = 30 ,

b = 3

And Sum of 4th column = b + 14 + e + 0 = b + e + 14 , Then

b + e + 14 = 30 , Substitute value of ' b ' and get

3 + e + 14 =  30 ,

e =  13

And Sum of 3rd column = 8 + d + 6 + 11 = d +25 , Then

d + 25 = 30 ,

d =  5

And Sum of 2nd row  =  2 + c + d + 14 =  c + d + 16 , So

c + d + 16 =  30 , Substitute value of ' d ' and get

c + 5 + 16 = 30 ,

c = 9

Therefore,

a + b + c + d + e = 15 + 3 + 9 + 5 + 13 =  45

Option ( A )                                                                  ( Ans )


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