A 1.0 kg block collides with a horizontal weightless spring of force constant 2.75Nm the block compresses the spring 4 m from the rest position . If the coefficient of kinetic friction between the block and horizontal surface is 0.25 the speed of the block at the instant of collision is

A 1.0 kg block collides with a horizontal weightless spring of force constant 2.75Nm the block compresses the spring 4 m from the rest position . If the coefficient of kinetic friction between the block and horizontal surface is 0.25 the speed of the block at the instant of collision is A ID • 2.75 BKI. TIN eanpr— 4.0 m mement klrwøc frßon 0.25, : (C) 0.8 rm-l 0.4—-1 (D) 8 tns-l

Dear student
use work-energy theorem12mv2=12kx2+μmgx12×1×v2=12×2.75×16+0.25×1×10×412×1×v2=22+10v2=(22+10)×2v=8 m/sRegards

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