A(1,2) and B(7,10) are two points. If P(x) is a point such that the angle APB is 60 degree and the area of the triangle APB is maximum, then which of the following is (are) correct? A) P lies on the straight line 3x+4y=36 B) P lies on any line perpendicular to AB C) P lies on the right bisector AB D) P lies on the circle passing through the points (1,2) and (7,10) and having a radius of 10 units. IT IS MULTICORRCT QUESTION Share with your friends Share 6 Neha Sethi answered this Dear student Since base AB of the △ is fixed,so for maximum area of △PAR,height of △ should be maximum,this is possible only when P lieson the ⊥ bisector of AB.Equation of ⊥ bisector of AB isy-6=-1-72-10x-4y-6=-34x-44y-24=-3x+123x+4y-36=0Also AB=10⇒AL=5So, AH=AL cosec60°=103 Correct options are: C and A Regards 2 View Full Answer