A(1,3) and C(-2/5,-2/5) are vertices of triangle ABC and the equation of internal angle bisector of angle ABC is x+y=2 then 1)equation of side BC is a)7x+3y-4=0 b)7x+3y+4=0 c)7x-3y+4=0 d)7x-3y-4=0.

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