A 100 0 ml dilute solution of Ag+ Is electrolysed for 15 mins With a current of 1 25mA - Chemistry - Electrochemistry

Question

A 100 0 ml dilute solution of Ag+ Is electrolysed for 15 mins
With a current of 1 25mA and the silver is removed completely What
was the initial (Ag+)

Vartika Jain · Accepted Answer

Dear Student,

Q= I×tor, Q=1 25×10-3×15×60=1
125 CAg+(aq) + e- → Ag(s)1 mole of electrons = 96500 CTherefore, moles of electron passed through the circuit=1
12596500=1
16×10-5It takes 1 mole of electrons to form AgTherefore, moles of Ag =1
16×10-51=1
16×10-5Moles of Ag= Moles of Ag+Now, [Ag+]=1
16×10-5×1000100=1 16×10-4 M

A 100.0 ml dilute solution of Ag+ Is electrolysed for 15 mins. With a current of 1.25mA and the silver is removed completely. What was the initial (Ag+)

A 100.0 ml dilute solution of Ag^{+ Is electrolysed for 15 mins. With a current of 1.25mA and the silver is removed completely. What was the initial (Ag+)}