A 100 ohm resistance and a capacitor of 100 OHM reactance are connected in series across a 220 V source. When the capacitor is 50% charged find the peak value of displacement current.  ​  

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Net resistance of the circuit= resistance+ capacitive reactanceZ=100+100=200 ohmaccording to the continuty equation, displacement current is the conduction currenthence ID=VZ=200200=1 Aand peak value = Io=2ID=1×1.414=1.414 A

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  • -157
displacement current is same as conduction current so displacement current=220/200
peak value=220*1.414/ 200= 1.1* 1.414= 1.55 Amp
  • -65
from where did u get 200?
 
  • -16
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