A 100Kg man jumps into swimming pool from a height of 5m It takes 0 4second for the water - Physics - Laws Of Motion

Question

A 100Kg man jumps into swimming pool from a height of 5m It takes 0
4second for the water to reduce his velocity to zero What is the
average force exerted by the water on the man?​

Sanjay Singh · Accepted Answer

Dear student
Velocity just before hitting the ground isv2-u2=2ghv2-02=2×g×5v=2×10×5=10m/sAcceleration in water isa=final velocity-initial velocitytime=0-100
4=-100
4=-1004=-25m/s2Average force F=m×average acceleration=100×(25)=2500 N (retarding force)Regards

A 100Kg man jumps into swimming pool from a height of 5m. It takes 0.4second for the water to reduce his velocity to zero. What is the average force exerted by the water on the man?​

A 100Kg man jumps into swimming pool from a height of 5m. It takes 0.4second for the water to reduce his velocity to zero. What is the average force exerted by the water on the man?