a 150g cricket ball moving horizontally at 20m/s was hit straight back to the bowler at 12m/s. if the contact with the bat lasted for 1/25 sec, the average force exerted by the bat on the ball is

change in momentum = mv-(-mu)= m(v+u) = 1501000×20+12 = 4.8 kg m/sforce = change in momentum/time = 4.81/25 = 120 N

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