a 1oocm3 block of lead that weighs 11N is carefully submerged in water .one cm3 of water weighs 0.0098 N
a.what volume of water does the lead displace?
b.how much does that volume of water weigh?
c.what is the bouyant force on the lead?
d.will the lead box sink or float in water?
(a)When an object is completely immersed in water,then the volume of water displaced will be equal to the volume of the object itself i.e,100cm3.
(b)Since one cm3 of water weighs 0.0098 N,so weight of 100 cm3 of water will be 100 x 0.0098=0.98N
(c) The magnitude of buoyant force acting on an object immersed in a liquid is equal to the weight of water displaced by the immersed object i.e, 0.98 N.
(d) We see that the buoyant force is less than the weight of object(11N).So the box will sink.