a^2+1a^2=2 then find a-1a ?

Dear student,

I f t h e q u e s t i o n i s t o f i n d (a - \frac{1}{a}) W e h a v e, a^{2} + \frac{1}{a^{2}} = 2 - - [1] t o f i n d (a - \frac{1}{a}) S q u a r i n g b o t h s i d e s {(a - \frac{1}{a})}^{2} = a^{2} + \frac{1}{a^{2}} - 2 \times a \times \frac{1}{a} \Rightarrow {(a - \frac{1}{a})}^{2} = 2 - 2 \Rightarrow {(a - \frac{1}{a})}^{2} = 0 \Rightarrow (a - \frac{1}{a}) = 0

Regards