A = 2 3 3

3 2 3

3 3 2 is matrix of order 3 * 3.

S.T : A^2 - 7A = 7I .Find A inverse ( without using any elementary transformation or adjoint method )


The question should be A2 - 7A = 8I

A=233323332A2=233323332×233323332    =4+9+96+6+96+9+66+6+99+4+99+6+66+9+69+6+69+9+4    =222121212221212122L.H.S.=A2-7A            =222121212221212122-7233323332            =222121212221212122-142121211421212114            =800080008            =8100010001            =8I            =R.H.S.Hence Proved.To find A-1, pre multiply by A-1, we have, A-1A2-7A= A-18IA-8 I=8 A-1 A-1=18A-8I A-1=18233323332-8100010001 A-1=18233323332-800080008 A-1=18-6333-6333-6 = 38-2111-2111-2  Hence, the answer.

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i did this by multiplying by A inverse .. Is it correct ?

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post multplication of A inverse is correct ...

you will get the eq. .. A-7I = 7( A inverse)

A inverse = -5/7 3/7 3/7

3/7 -5/7 3/7

3/7 3/7 -5/7

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