A 200V variable frequency ac source is connected to series combination of
L = 5H, C = 80µF and R = 40Ω calculate
1)Current amplitude at resonance
2)The power dissipation in the circuit
3) angular frequency of the source to get maximum current in the circuit. Reply fast.
Here,
Vrms = 200V
L = 5H
C = 80×10-6F
R = 40Ω
1.
The amplitude of current of a series LCR ckt is given by
Io = V0/√{(XL-XC)2+R2}
At resonance XL=XC
Thus,
Vo = √2Vrms
Vo = √2×200/R
=> I0 = √2×200/40 = 5√2A
2.
For power with variable frequency
