A 2l vessel contains oxygen at a pressure of 380mm Hg at 27°c. 1.40g of N2 gas is introduced in the vessel. Will the pressure of the gaseous mixture increase or decrease and to what extent?

Dear Student,

We know thatPV=nRTP1=380 mmHg=380760atm =0.5 atmV=2 LR=0.0821Latmmol-1K-1T=27+273=300 KNow, moles of oxygen in the vessel, n=P1VRTor, n=0.5×20.0821×300=0.0406 molMoles of N2 introduced =massmolar mass=1.4028=0.05 molSo, total moles of gas in the vessel,n' = 0.05+0.0406=0.0906 molThe pressure will obviously increases as it is directly related to the number of moles. Here, moles is increasing, so pressure will also increase. now pressure of the vessel, P2 =n'RTV=0.0906×0.0821×3002=1.1157 atmTherefore, increase in pressure = P2-P1=1.1157-0.5 atm =0.6157 atm = 0.6157×760 mmHg =378.88 mmHg

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