A 3 cm thick iron open box is made whose external dimensions are 78cm ?.54cm ?.12cm. Find the weight of the box if its density is 60gm/cm^2

Dear Student,

$$\begin{gathered} Thickness of the iron sheet = 3 cm \\ External dimensions at the box = 78\times 54\times 12 \\ therefore internal dimensions of the box = 72\times 48\times 9 \\ Volume of the iron used in making the box \\ = External volume of the box - internal volume \\ = \left(78\times 54\times 12\right)-\left(72\times 48\times 9\right) \\ = 50544 - 3110 \\ = 19440 c{m}^3 \\ Weight = Volume \times density \\ = 19440 \times 60gm \\ = \frac{19440 \times 60}{1000} kg \\ = 1166.4 Kg \end{gathered}$$

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