A 3g of sample of Na2CO3.10H2O is heated to a constant mass. How much anhydrous salt remains?
Dear Student,
Washing soda on heating converted to anhydrous Sodium carbonate.
Na2CO3: 2(23.0) + 12.0 + 3(16.0) = 106.0 g
H2O: 18.0 g
Na2CO3• 10H2O (total): (106+10*18) = 286 g
286 g of Na2CO3• 10H2O produces = 106 g of Na2CO3
3 g of Na2CO3• 10H2O produces = (106*3)/286 g of Na2CO3
= 1.11 g of Na2CO3
Mass of anhydrous Salt = 1.11 g
Regards
Washing soda on heating converted to anhydrous Sodium carbonate.
Na2CO3: 2(23.0) + 12.0 + 3(16.0) = 106.0 g
H2O: 18.0 g
Na2CO3• 10H2O (total): (106+10*18) = 286 g
286 g of Na2CO3• 10H2O produces = 106 g of Na2CO3
3 g of Na2CO3• 10H2O produces = (106*3)/286 g of Na2CO3
= 1.11 g of Na2CO3
Mass of anhydrous Salt = 1.11 g
Regards