a 4 ohm resistance wire is doubled on it calculate the new resistance of the wire

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Ruhhi Ralhan answered this

Dear Student,

In this query we consider wire double on it means to fold the length of wire. It means its length will get half and area of cross section will get double.

Let the resistance of the wire originally 'R' of length 'l' and area of cross-section 'A' with resistivity of material is 'ρ', Then

$R = ρ \frac{l}{A} = 4 Ω$

Now, for new arrangement,

$ρ' = ρ l' = \frac{l}{2} A' = 2 A Thus, R' = ρ' \frac{l'}{A'} = ρ \frac{(\frac{l}{2})}{2 A} = \frac{1}{4} (ρ \frac{l}{A}) = \frac{1}{4} R = \frac{1}{4} \times 4 = 1 Ω$

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R=p. l/A

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answer is 1 ohm

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Resistivity is the property of a material But resistance Is the Ratio of potential difference across a conductor through current flowing through it

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Two different resistor when connected in series have equivalent resistance of 8 ohm and when connected in parallel then the equivalent is 2 ohm. Find details the resistance of each resistance.

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Tanya answered this

A 4ohm resistance wire is doubled on it. Calculate the new resistance of the wire.

-3

Indu answered this

p' = p

l' = l / 2

A' = 2A

Thus,

R' = p' l'/A' = p (l /2) ÷ 2A = !/4 (p l / A) = 1/4R = 1/4 × 4 = 1Ω.

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Hope it is helpful.....

-1

Nikhil answered this

Resistance becomes 1ohm

-2

Akshit Goel answered this

Length getting doubled means that length of wire gets halted , area of cross section gets doubled , therefore , l=l/2 A=2A R=PL/A NOW IF we solve it we get resistance as 1 ohm

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Bhawana answered this

We know,
R=pl/a
Where R is resistance
P is resistivity
l is length
a is area of cross section

If resistance is doubled then
R'= 2(pl)/a where R' is a new resistance

R' = 2R
= 2*4 (as resistance is given 4 ohm)
= 8 ohm
Hence new resistance is 8 ohm

-1

Rahul Kumar answered this

Length of wire is doubled (2l)
As we know that ,if length is double then the resistance is half.
Hence, l inversely proportional to The
So,2l = 1/2 ? 4
=2 ohm resistance .
Hope you understand.
But might be wrong

Bhawana answered this

We know
P= RA/l

Now, initially we have -
R= 4 ohm
Area = A
Length = l
So,
P=4A /l -----------(1)

Now when wire get doubled then -
Length get half i.e l/2
Area of Cross - section get doubled i.e 2A
Resistance becomes R'
So,
P=R'2A/l/2
= 4R'A /l ---------- (2)
Now we know that resistivity of a wire never get affected by change in shape and size. So,
Eqn- (1) = Eqn- (2)

4A/l = 4 R'A/l
1 = R'
Hence new resistance is 1 ohm

Bhawana answered this

We know,
P=RA/l
where p is resistivity
R is resistance
A is area of Cross section
l is length of conductor
Wire is of 4 ohm so,
Initially p= 4A /l

When wire is doubled then,
Length get halved i.e l/2
Area get doubled i.e 2A
Let new resistance be R's
So, p'= R'2A/l/2 = 4R'A/l

Now we know that resistivity of a same wire is not depends on resistance. So, if here resistance varies then it is not necessary that the resistivity also changes.
P' = P
4A / l = 4R'A/ l
R' = 1
Hence new resistance is 1 ohm

Bhola Chhonker answered this

Resistance is directly proportional to length of wire
when length of wire is doubled then resistance will also double

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4 = ?l/A

R' = ?(2l)/A = 2 ? ?l/A = 2 ? 4 = 8 ?

THIS IS TRUE ONLY IF WIRE IS NOT STRETCHED AND VOLUME CHANGES.

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Sachin Jha answered this

Dear Student,

In this query we consider wire double on it means to fold the length of wire. It means its length will get half and area of cross section will get double.

Let the resistance of the wire originally 'R' of length 'l' and area of cross-section 'A' with resistivity of material is '?', Then

?

Now, for new arrangement,

?

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It's like adding up one more identical resistance in the series. Resistance will become 8 ohm.

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Resistivity=voltage

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Sherin Sabu answered this

Resistance= (pl)/a

l=length of wire

a=area of wire

Wire is doubled so length will be doubled.

Let's assume R initial resistance..

R'= new resistance

R'=(2pl)/a

R'=2R

R'=2*4=8 ohm

New resistance is 8 ohm

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Length is directly proportional to resistance,
So the resistance of the wire will be 2?4=8ohm

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Ashutosh Kumar Yadav answered this

We consider wire is doubled on it means to fold the length of wire. It means its length will get half and area of cross section will get doubled. Thus, R' = p' l'/A' = p (l /2) ? 2A = !/4 (p l / A) = 1/4R = 1/4 ? 4 = 1?.

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