a 4 ohm resistance wire is doubled on it  calculate the new resistance of the wire 


 

Dear Student,

In this query we consider wire double on it means to fold the length of wire. It means its length will get half and area of cross section will get double.

Let the resistance of the wire originally 'R' of length 'l' and area of cross-section 'A' with resistivity of material is 'ρ', Then

Now, for new arrangement,

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It is surely correct . Thanls for giving answer.
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Thank you
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I don't umderstand by 'doubled on it' ..
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The answer is 1
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R=p. l/A

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answer is 1 ohm
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Here is the answer.....

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Resistivity is the property of a material But resistance Is the Ratio of potential difference across a conductor through current flowing through it
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Two different resistor when connected in series have equivalent resistance of 8 ohm and when connected in parallel then the equivalent is 2 ohm. Find details the resistance of each resistance.

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hope it will help u

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A 4ohm resistance wire is doubled on it. Calculate the new resistance of the wire.

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p' = p

l' = l / 2

A' = 2A

Thus, 

R' = p' l'/A' = p (l /2) ÷ 2A = !/4 (p l / A) = 1/4R = 1/4 × 4 = 1Ω.
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Hope it is helpful.....

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Resistance becomes 1ohm
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Length getting doubled means that length of wire gets halted , area of cross section gets doubled , therefore , l=l/2 A=2A R=PL/A NOW IF we solve it we get resistance as 1 ohm
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May this help you

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those substances through which electricity does not flow is called insulator
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1 ohm is answer
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1 ohm is answer
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nothing
 
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Here's the answer for;it

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We know,
R=pl/a
Where R is resistance
P is resistivity
l is length
a is area of cross section

If resistance is doubled then
R'= 2(pl)/a where R' is a new resistance

R' = 2R
= 2*4 (as resistance is given 4 ohm)
= 8 ohm
Hence new resistance is 8 ohm
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Length of wire is doubled (2l)
As we know that ,if length is double then the resistance is half.
Hence, l inversely proportional to The
So,2l = 1/2 ? 4
=2 ohm resistance .
Hope you understand.
But might be wrong
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We know
P= RA/l

Now, initially we have -
R= 4 ohm
Area = A
Length = l
So,
P=4A /l -----------(1)

Now when wire get doubled then -
Length get half i.e l/2
Area of Cross - section get doubled i.e 2A
Resistance becomes R'
So,
P=R'2A/l/2
= 4R'A /l ---------- (2)
Now we know that resistivity of a wire never get affected by change in shape and size. So,
Eqn- (1) = Eqn- (2)

4A/l = 4 R'A/l
1 = R'
Hence new resistance is 1 ohm
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We know,
P=RA/l
where p is resistivity
R is resistance
A is area of Cross section
l is length of conductor
Wire is of 4 ohm so,
Initially p= 4A /l

When wire is doubled then,
Length get halved i.e l/2
Area get doubled i.e 2A
Let new resistance be R's
So, p'= R'2A/l/2 = 4R'A/l

Now we know that resistivity of a same wire is not depends on resistance. So, if here resistance varies then it is not necessary that the resistivity also changes.
P' = P
4A / l = 4R'A/ l
R' = 1
Hence new resistance is 1 ohm
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Resistance is directly proportional to length of wire
when length of wire is doubled then resistance will also double

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Hope it is helpful for u

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Hope ! it will help you

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Hope ! It will help you

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Here is your answer

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4 = ?l/A

R' = ?(2l)/A = 2 ? ?l/A = 2 ? 4 = 8 ?

THIS IS TRUE ONLY IF WIRE IS NOT STRETCHED AND VOLUME CHANGES.
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Dear Student,

In this query we consider wire double on it means to fold the length of wire. It means its length will get half and area of cross section will get double.

Let the resistance of the wire originally 'R' of length 'l' and area of cross-section 'A' with resistivity of material is '?', Then

?

Now, for new arrangement,

?
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Resistance= (pl)/a

l=length of wire

a=area of wire

Wire is doubled so length will be doubled.

Let's assume R initial resistance..

R'= new resistance

R'=(2pl)/a

R'=2R

R'=2*4=8 ohm

New resistance is 8 ohm
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