a 40 kg skater moving at 4ms eastwards collides head on with a 60 kg skater travelling at 3ms westwards - Science - Force and Laws of Motion

Question

a 40 kg skater moving at 4ms eastwards collides head on with a
60 kg skater travelling at 3ms westwards if the two skates remain
in contact, what is their final velocity?

Roopa jayasimha · Accepted Answer

Given M1=40 kg U1=4 m/s

M2=60 kg U2=-3m/s (since it is in opposite
direction)

After collision, both move together, hence
mass = M1+M2 = 40+60 = 100 kg

From the law of conservation of momentum we
have

M1 U1+ M2 U2= (M1 + M2)V

40*4 - 60*3 = 100V

Hence, V = -0 2 m/s

i e , The body moves in the orginal direction
of the 60kg mass (since it had the higher
momentum)

a 40 kg skater moving at 4ms eastwards collides head on with a 60 kg skater travelling at 3ms westwards . if the two skates remain in contact, what is their final velocity?