a 40 ohm resistor , 3 mH inductor and 2 uF capacitor are connected in series in 110 V , 5000 Hz a.c. source . clculate the value of the current in the circuit

Dear Student,


XL=ωL=10000π*3*10-3=94.25 ohm .XC=1ωc=110000π*2*10-6=15.91 ohm .impeadace Z=402+94.25-15.912=88 ohm current I=VZ=11088=1.25 ARegards

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