A 5 L cylinder contains 10 moles of oxygen at 27 degrees celsius Due to sudden leakage through the - Chemistry - Thermodynamics

Question

A 5 L cylinder contains 10 moles of oxygen at 27 degrees celsius
Due to sudden leakage through the hole, all the gas escaped into
the atmosphere and the cylinder got empty If the atmospheric
pressure is 1 atm, calculate the work done by the gas

Pankaj Singh · Accepted Answer

Vinitial = 5L

T = 27 +273 =300K

Vfinal = nRT/P = (10 x 0.0821 x 300)/ 1.0 = 246.3 L

$Δ V = V_{f i n a l} - V_{i n i t i a l}$ = 246.3 -5 =241.3L

$W_{\exp} = - p Δ V = - 1 \times 241.3 = 241.3 L a t m = - 241.3 \times 101.3 = - 24443.7 J$

A 5 L cylinder contains 10 moles of oxygen at 27 degrees celsius. Due to sudden leakage through the hole, all the gas escaped into the atmosphere and the cylinder got empty. If the atmospheric pressure is 1 atm, calculate the work done by the gas.