A 5 L cylinder contains 10 moles of oxygen at 27 degrees celsius. Due to sudden leakage through the hole, all the gas escaped into the atmosphere and the cylinder got empty. If the atmospheric pressure is 1 atm, calculate the work done by the gas.

Vinitial = 5L

T = 27 +273 =300K

Vfinal = nRT/P = (10 x 0.0821 x 300)/ 1.0 = 246.3 L

 

 = 246.3 -5 =241.3L

  • 65

 v = nrt/p

v= 10*8.314*300/1 = 24942 J

w= -p(change in volume)

w=-1*24942= -24942 or 24.9 kj

  • -11
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