a 5% (w/v) solution of cane sugar (mol wt=342) is isotonic with 1% (w/v) solution of substance x. the molecular weight of X is
Ans. is 68.4 g mol-1
Isotonic means both the solutions have same concentration.
Mass of cane sugar = 5 g dissolved in 100 mL water
Mass of substance x = 1 g dissolved in 100 mL water
Molar mass of cane sugar = 342 g mol-1
Molar mass of substance x = ?
Concentration =
So, on equating the concentrations of both, we can find the molecular mass of substance x:
Isotonic means both the solutions have same concentration.
Mass of cane sugar = 5 g dissolved in 100 mL water
Mass of substance x = 1 g dissolved in 100 mL water
Molar mass of cane sugar = 342 g mol-1
Molar mass of substance x = ?
Concentration =
So, on equating the concentrations of both, we can find the molecular mass of substance x: