A 60V, 10W electric lamp is to run on 100V-60Hz mains 1)Calculate the inductance of inductor required 2)If a resistor is to be used in a plane of inductor to achieve the same result, calculate its value 3) Calculate the total power of the circuit in both the cases Share with your friends Share 12 Ved Prakash Lakhera answered this a) We know power of an elctric lamp P = V2R.or R = V2P=60×6010=360 ohm.and I = VR=60360=1/6 A.now A. C. circuit containing LR circuit, V = Z×I = R2+ω2L2 ×INOW 100 =R2+ω2L2 ×16OR 600 = 3602+4π2×602L2OR 360000 = 129600+4π2×602L2OR 230400 = 4π2×602L2OR L2 = 2304004π2×602=2304×7×74×22×22×36OR L = 48×72×22×6=2422=1.27 henry. b) In case only resistor is used then, 100 = R0×I =R0×16OR R0 = 100×6 = 600 ohm.c) power in both of the cases, P = V×I cosϕ= 100×16×RR2+ω2L2=100×16×360600=10W. and in second case it is , power consumed P = V×I cosϕ=V×I×cos90°=0because in case of inductor only the phase angle between the current and voltage is 90°. 8 View Full Answer Jane Carolyn answered this Searching for the same answer ;) 1
