A 75 kg man weighs 735 N on the Earth's surface How far above the surface of the Earth - Physics - Gravitation

Question

A 75 kg man weighs 735 N on the Earth's surface How far above the
surface of the Earth would he have to go so as to lose 10% of his
body weight?

Shivam Kumar · Accepted Answer

Dear Student,

Here, R is radius of earth(6400 km),g'=gRR+h2Multplying by massw'=wRR+h27351-10100=73564006400+h2  Weight loss = 10%64006400+h2=901006400+h6400=10090=109
48simplyfying9 48h=6400×0 52h=6400×0 529
48=351 km

Regards,

A 75 kg man weighs 735 N on the Earth's surface. How far above the surface of the Earth would he have to go so as to lose 10% of his body weight?