A 8 kg body perform simple harmonic motion of amplitude 30 sec. The resorting force is 60 newton. when the displacement is 30 sec . find time period , acceleration , potential energy , kinetic energy  at when displacement is 12 cm .

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Given that
m=8 kg, a=30cm=0.3 mF=60 N when x=0.3 m F=kx k=600.3=200 N/mbut k=mω2  soω=km=2008=5 rad/sTime period T=2πω=2×3.145=1.256 sWhen x=12 cm =0.12macceleration a=ω2x=52×0.12=3 m/s2Potential energyU=12kx2=12×200×0.122=1.44 Jkinetic energyK=12ka2-x2=12×200×0.32-0.122=7.56 J

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