A and B throw a dice alternatively till one of them gets a number greater than four and wins the game. If A starts the game, what is the probability of B winning?

Probability of winning = getting a number greater than 4or getting 5 and 6 = 26=13So probability of loosing = 1-13=23Now if we want that B wins so AloseBwin+AloseBloseAloseBwin+AloseBloseAloseBloseAloseBwin+....=23×13+23×23×23×13+23×23×23×23×23×13...It is a GP with first term a = 29 and common ratio r = 49So sum of infinite GP series=a1-r=291- 49=25

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Probability of B winning will be equal to the probability of loosing of A
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@Ishan Watts, can you show it how?
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