A,B and C are three mutually exclusive and exhaustive events. IfP(A)=2/7 and P(B)=1/7 then find P(C) Share with your friends Share 2 Neha Sethi answered this Dear student PA=27PB=17Since A,B,C are mutually exclusive and exhaustive events So, A∪B∪C=S where S=sample space⇒PA∪B∪C=PS⇒PA∪B∪C=1 As PS=1⇒PA+PB+PC=1 If A,B,C are mutually exclusive events then PA∪B∪C=PA+PB+PC⇒27+17+PC=1⇒PC=1-37⇒PC=47 Regards 3 View Full Answer Sakshi answered this This is similar to your question 1
