A, B, C, D buy one gift each of Christmas Santa Party at office and they are supposed to give the gift to someone else in their group (A, B, C, D) other than themselves. In how many ways the gifts can be exchange it? Share with your friends Share 0 Aarushi Mishra answered this We will use exclusion and inclusion principleNumber of ways of arranging n things at n places such that no thing is at its right place is given byn!-C1nn-1!+C2nn-2!-C3nn-3!+.....+-1n Cnnn-n!Heren=4Possible number of ways in which they can give gift to one another, other than themselves, will be same as arrangement of 4 things at 4 places such that no thing is at its right place i.e. it is not with the person who bought itTotal arrangements=4!-C144-1!+C244-2!-C344-3!+C444-4!=24-24+12-4+1=9 0 View Full Answer Champ Jee answered this I am getting 64. Is that right? I dont know. 1 Manish Yadav! answered this Ur question is not clear 0