​A B D PLZZZZZ

Dear student,
as you are asking for multiple question.
so i suggest you to ask these questions seprately.
here i am answering its A part only.
let y=x2+2x+4x+2
y(x+2)=x2+2x+4
yx+2y=x2+2x+4
x2+x(2-y)+(4-2y)=0
since x is real so its Discriminent must be non-negative.
i.e B2-4AC0
or (2-y)2-4(4-2y)0
or y2+4y-120
or ​y2+6y-2y-120
or (y+6)(y-2)0
y-6 or y2
minimum value of y will be 2

enjoy

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(A) is R
(B) is P
(D) is Q

this is not log topic this is iit jee matrix topic
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