A bag contains 21 tickets numbered from 1 to 21. Two tickets are drawn. Find the probability that the sum of the numbers is an even number?

From 1 to 21, there are 10 even and 11 odd numbersSo we have to choose either both odd or both even to get the sum even.SO the required probability is = 10C2+11C221C2 

  • 0
What are you looking for?