A bag contains 5 red , 7 green and 4 white balls, three balls are drawn one after the other without replacement. Find the probability that the balls drawn are white, green and green respectively. Share with your friends Share 3 Rahul Raj answered this Dear student probability of first ball to be white = 416after this white ball is picked, we have 15 balls of which 7 is greenprobability of green = 715after this green ball is picked, we have 14 balls of which 6 is greenprobability of green = 614required probability = 416×715×614=120 Regards 16 View Full Answer Ashutosh answered this easy question. XD -6 Kalpesh Avg answered this This problem is based on combination since it is without replacement 4/16 + 7/16*6/15 this should give the answer...... -9
