A ball is projected vertically down with an intial velocity from a height of 20 m on to a horizontal floor. During the impact it loses 50 percent of its energy and rebounds to the same height, what will be the initial velocity of its projection?

Dear Student, 
Please find below the solution to the asked query: 
50% of (PE+KE)=PE12×mgh+12mv2=mgh2gh+v2=4ghv=2gh=2×9.8×20=19.8 m/s
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