A ball is projected with initial velocity u at angle θ to the horizontal. Then horizontal displacement covered by ball as it collides third time to the ground would be, if coefficient of restitution is e: (A) 1 + e u 2 sin 2 θ g (B) e u 2 sin 2 θ g (C) 1 - e u 2 sin 2 θ g (D) 1 + e + e 2 u 2 sin 2 θ g Share with your friends Share 15 Shobhit Mittal answered this Dear Student, the x component of the velocity will always be ucosθRrange of first projectile R=u2sin2θgvelocity after first collision u'= ucosθ2+ eusinθ2=ucosθ2+e2sinθ2angle sin2α=esin2θcosθ2+e2sinθ2range of second projectileR'=u'2sin2αg=u2cosθ2+e2sinθ2esin2θcosθ2+e2sinθ2g=eu2sin2θgrange of second projectileR''=e2u2sin2θgtotal displacement x=R+R'+R''=u2sin2θg+eu2sin2θg+e2u2sin2θgoption DRegards 8 View Full Answer