# A ball is thrown horizontally from the top of a tower with a velocity of 40 ms-1. Take g = 10 ms-2 a) Find the horizontal and vertical displacement after 1,2,3,4,5 seconds, then the path of         the motion of ball.  b) If the ball reaches the ground in 4 seconds, find the height of the tower.

Dear student,

For horizontal distance, gravity plays no role.

The path of the ball will be parabolic

(b) When the ball hits the ground, its final velocity is zero
$H=\frac{{u}^{2}}{2g}\phantom{\rule{0ex}{0ex}}H=\frac{{40}^{2}}{20}=80m$