• a ball is thrown vertically upwards with initial velocity u .find distance covered by it in last t second.options are 1/2gt2or ut +1/2gt2 .

we have the following equivalence...

The distance covered by the ball during the last t seconds of its upward motion = The distance covered by it in first t seconds of its downward motion

now, during downward motion

s = ut + (1/2)at2


u = 0 [for first t seconds]

a = g


s = (1/2)gt2

  • -1

I guess none of the given option is correct !!!

  • 1
What are you looking for?