• a ball is thrown vertically upwards with initial velocity u .find distance covered by it in last t second.options are 1/2gt2or ut +1/2gt2 .

we have the following equivalence...

The distance covered by the ball during the last t seconds of its upward motion = The distance covered by it in first t seconds of its downward motion

now, during downward motion

s = ut + (1/2)at2

here,

u = 0 [for first t seconds]

a = g

so,

s = (1/2)gt2

  • -1

I guess none of the given option is correct !!!

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