A ballon is rising upwards with an acceleration. A stone is dropped from the ballon, when the ballon is at a height of 50.4m . The stone reaches the ground after 6s. What was the velocity of the ballon when it was dropped?

Dear student,
A stone is dropped from a rising balloon at a height of 50.4 m above the ground and it reaches the ground in 6 s.
If the stone were dropped from a stationary balloon, the time t taken for it to reach the ground would have been given by
50.4 = (1/2)*9.8*t2
=> t =  (50.4/4.9)
=> t = 10.26 s .
But the stone takes 6 s to reach the ground. If the upward velocity of the balloon in V.
50.4 = -V*6 + (1/2)*9.8*36
=> 6*V = 126
=> V = 21 m/s
The balloon is rising up at 21 m/s when the stone is dropped from it.
Regards

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