a biconvex spherical lens of has a focal length of 20 cm.if it is split along a plane vertically into two halves to form two plano-convex lenses. ,then what will be the length of each plano-convex lens......... what if the lens be cut horizontally....... Share with your friends Share 16 Abhay Kumar answered this By lens maker formula we know that:1/fnet = (μl/μs-1)(1/f1 - 1/f2)where :fnet = is the focal length of the combinationμl= refractive index of lensμs= refractive index of surroundingf1 & f2 are focal length of either side.before the lens was cut:1/20 =(μl/μs-1)(2/f) 1/f= 1/40 (μl/μs-1)after the lens is cut:1/f'net = (μl/μs-1)(1/f1 - 1/f2)1/f'net = (μl/μs-1)(1/f - 1/∞)infinity as the other side is plane after cutting it...put the value of 1/f1/f'net = (μl/μs-1)(1/f )1/f'net = (μl/μs-1) 1/40 (μl/μs-1)1/f'net = 1/40f'net = 40 cmand their would be no effect ot on the focal lens if cut horizontally. 7 View Full Answer
